2v^2=-13v

Solution for 2v^2=-13v equation:

2v^2=-13v

We move all terms to the left:

2v^2-(-13v)=0

We get rid of parentheses

2v^2+13v=0

a = 2; b = 13; c = 0;
Δ = b2-4ac
Δ = 132-4·2·0
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{169}=13$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-13}{2*2}=\frac{-26}{4}
=-6+1/2
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+13}{2*2}=\frac{0}{4}
=0
$